Study Material Solution

NCERT 6TH CLASS MATHS RATIO & PROPPRTION PART- lll

ANSWER KEY - Multiple Choice questions: 1.  (a) 5 times      Hint:     10 = 5 × 2 2. (a) 2: 3     Hint:     80000 = 2 × 40000 3. (a) 2:3     Hint:     20/30=2/3= 2: 3 4. (a) 1:2     Hint:    25/(25+25 )=25/50   = 12 = 1: 2 5.  (b) 5:4      Hint:      150/120  = 15/12  = 5/4  = 5: 4 6.  (a)     Hint:     50,000/3,00,000  = 1/6  = 1: 6 7. (b) 3:1     Hint:     6/2  = 3/1  = 3: 1 8.  (d) 5:4.      Hint:      50/40  = 5/4  = 5: 4 9.  (a) 2:5      Hint:      1 m = 100 cm      40/100  = 2/5  = 2: 5 10.  (a) 1:2        Hint:        4/8  = 1/2  = 1: 2 11. (c) 6: 9       Hint:        2: 3 = 2/3= (2×3)/(3×3)  = 6/9= 6: 9 12.  (a) 1:2        Hint:               13.  (d) 3: 2        Hint:        12: 8 = 12/8= (12÷4)/(8÷4)  = 3/2= 3: 2 14.  (c) 1: 25        Hint:        20: 500 = 20/500=1/25= 1: 25 15.  (b) 5:12        Hint:       1 hour = 60 minutes       25: 60 = 25/60=5/12= 5: 12 Match The Following:          Fill in the blanks: 1. If 4, a, a, 36 are in proportion then a is equal to 12. 2. 32 m: 64 m:: 6 Sec: 12 Sec. 3. 5: 4 = 30: 24. 4. If a = 2b then a: b = 2: 1. True /False: 1.  True 2.  False 3.  True 4.  False Very Short Answer: 1. X: 6 = 25: 5           2.  It is given that   Weight of 25 copies = 5 kg   ∴ Weight of 1 copy = 5 ÷ 25 = 1/5 kg   ∴ Weight of 30 copies = 30 ×1/5= 6 kg 3.  45km: 60km = 45/60  =  (45÷15)/(60÷15)   [∴ H.C.F.(45, 60) = 15] = 3/4 = 3: 4     12 hours: 15 hours = 12/15=(12÷3)/(15÷3 )  [∴H.C.F.(12, 15) = 3] =4/5=4:5     Since, the two ratios are not equal, therefore the given statement is false(F). 4.  24: 27 = 24/27=(24÷3)/(27÷3)  [∴H.C.F.(24, 27) = 3] = 8/9=8:9      8: 9 = 24: 27      ∴ 8: 9:: 24: 27 is true(T). 5. 7.5 liter: 15 liter     6.              7.  Let 2A = 3B = 4C = x      8.  The given numbers are not in the same units. So, converting them into same units.    1.5 m = 1.5 × 100 cm = 150 cm    [∵ 1 m = 100 cm]     ∴ The required ratio is 75 cm: 150 cm.           ∴ Required ratio = 1: 2 9.             Thus, 9: 15 and 6: 10 are the two equivalent ratios of 3: 5. 10.           Short Answer: 1.         ∴ They are equivalent ratios. 2.  Sum = 2 + 3 = 5   ∴ First part = 2/5  × 60 =24 5   ∴ Second part =3/5  × 60 =36 5   Thus, the required two parts = 24 and 36.      3.        4. Total money deposited = ₹ 2050    Amount of money withdrawn = ₹ 410    Amount of money left in the bank = ₹ 2050 – ₹ 410 = ₹ 1640    (a) Ratio of money withdrawn to the total money deposited            ∴ Required ratio = 1: 5     (b) Ratio of money withdrawn to the money left in the bank                    ∴ Required ratio = 1: 4 5. Total number of students = 180     Number of girls = 75     Number of boys = 180 – 75 = 105    ∴ Ratio of number of girls to the number of boys                    Required ratio = 5: 7 6.  Here, sum of ratios = 2 + 7 + 1 = 10     ∴ Total quantity of green paint = 64 litres    Quantity of blue paint =2/10× 64 = 12.8 litres    Therefore, the required blue paint = 12.8 litres. 7.   (a)  Number of squares = 2       Number of triangles = 3 2      ∴ Ratio =2/3 or 2: 3      (b) Number of circles = 3      Number of rectangles = 3      ∴ Ratio =3/3  or 1: 1 Long Answer: 1. (a) Number of shaded parts = 4     Number of unshaded parts = 12                Required ratio = 1: 3         (b) Number of shaded parts = 2     Number of unshaded parts = 4                 Required ratio = 1: 2 2. We have 20, 25, 12, 15     Product of extremes = 20 × 15 = 300     Product of middles = 25 × 12 = 300     Since both the products are same.     ∴ The four numbers 20, 25, 12, 15 are in proportion. 3.  Let the third term be x.     ∴ 32, 112, x and 217 are in proportion.     ∴ 32: 112:: x: 217               Thus, the third term = 62. 4.  (a) Since 8, x, x, 50, are in proportion.     ∴ x × x = 8 × 50     ⇒ x2 = 400    ∴ x = 20     (b) Since 36, 90, 90, x are in proportion.     ∴ 36 × x = 90 × 90     ⇒x=(90×90)/36=225     ∴ x = 225 5.  Number of tables purchased in ₹ 7500 = 10      Number of tables purchased in ₹ 1 =10/7500     ∴ Number of tables purchased in ₹ 9000     =(10×9000)/75000=12 6. Number of pens in 1 packet = 12     Number of pens in 39 packets = 12 × 39 = 468     Number of pens in 1 packet = 10     Number of pens in 52 packets = 10 × 52 = 520     Now cost of 468 pen = ₹ 374.40         Assertion and Reason Answers: (1) (a) A is false but R is true (2) (b) Both A and R are true and R is the correct explanation of A