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NCERT 6TH CLASS MATHS RATIO & PROPPRTION PART- lll

ANSWER KEY -

Multiple Choice questions:
1.  (a) 5 times
     Hint:
    10 = 5 × 2

2. (a) 2: 3
    Hint:
    80000 = 2 × 40000

3. (a) 2:3
    Hint:
    20/30=2/3= 2: 3

4. (a) 1:2
    Hint:
   25/(25+25 )=25/50   = 12 = 1: 2

5.  (b) 5:4
     Hint:
     150/120  = 15/12  = 5/4  = 5: 4

6.  (a)
    Hint:
    50,000/3,00,000  = 1/6  = 1: 6

7. (b) 3:1
    Hint:
    6/2  = 3/1  = 3: 1

8.  (d) 5:4.
     Hint:
     50/40  = 5/4  = 5: 4

9.  (a) 2:5
     Hint:
     1 m = 100 cm
     40/100  = 2/5  = 2: 5

10.  (a) 1:2
       Hint:
       4/8  = 1/2  = 1: 2

11. (c) 6: 9
      Hint:
       2: 3 = 2/3= (2×3)/(3×3)  = 6/9= 6: 9

12.  (a) 1:2
       Hint:
     
       

13.  (d) 3: 2
       Hint:
       12: 8 = 12/8= (12÷4)/(8÷4)  = 3/2= 3: 2

14.  (c) 1: 25
       Hint:
       20: 500 = 20/500=1/25= 1: 25

15.  (b) 5:12
       Hint:
      1 hour = 60 minutes
      25: 60 = 25/60=5/12= 5: 12

Match The Following:
    
   


Fill in the blanks:
1. If 4, a, a, 36 are in proportion then a is equal to 12.
2. 32 m: 64 m:: 6 Sec: 12 Sec.
3. 5: 4 = 30: 24.
4. If a = 2b then a: b = 2: 1.

True /False:
1.  True
2.  False
3.  True
4.  False

Very Short Answer:
1. X: 6 = 25: 5
     
   
2.  It is given that
  Weight of 25 copies = 5 kg
  ∴ Weight of 1 copy = 5 ÷ 25 = 1/5 kg
  ∴ Weight of 30 copies = 30 ×1/5= 6 kg

3.  45km: 60km = 45/60  =  (45÷15)/(60÷15)   [∴ H.C.F.(45, 60) = 15] = 3/4 = 3: 4
    12 hours: 15 hours = 12/15=(12÷3)/(15÷3 )  [∴H.C.F.(12, 15) = 3] =4/5=4:5
    Since, the two ratios are not equal, therefore the given statement is false(F).

4.  24: 27 = 24/27=(24÷3)/(27÷3)  [∴H.C.F.(24, 27) = 3] = 8/9=8:9
     8: 9 = 24: 27
     ∴ 8: 9:: 24: 27 is true(T).

5. 7.5 liter: 15 liter
   

6.    
      
 
7.  Let 2A = 3B = 4C = x
    


8.  The given numbers are not in the same units. So, converting them into same units.
   1.5 m = 1.5 × 100 cm = 150 cm
   [∵ 1 m = 100 cm]
    ∴ The required ratio is 75 cm: 150 cm.
     
    ∴ Required ratio = 1: 2

9.    
   
    Thus, 9: 15 and 6: 10 are the two equivalent ratios of 3: 5.

10.    
     


Short Answer:
1.    
  
 ∴ They are equivalent ratios.

2.  Sum = 2 + 3 = 5
  ∴ First part = 2/5  × 60 =24 5
  ∴ Second part =3/5  × 60 =36 5
  Thus, the required two parts = 24 and 36.
    
3. 
     

4. Total money deposited = ₹ 2050
   Amount of money withdrawn = ₹ 410
   Amount of money left in the bank = ₹ 2050 – ₹ 410 = ₹ 1640
   (a) Ratio of money withdrawn to the total money deposited

       
   ∴ Required ratio = 1: 5
 
  (b) Ratio of money withdrawn to the money left in the bank
       
       
   ∴ Required ratio = 1: 4

5. Total number of students = 180
    Number of girls = 75
    Number of boys = 180 – 75 = 105
   ∴ Ratio of number of girls to the number of boys
      
       
    Required ratio = 5: 7

6.  Here, sum of ratios = 2 + 7 + 1 = 10
    ∴ Total quantity of green paint = 64 litres
   Quantity of blue paint =2/10× 64 = 12.8 litres
   Therefore, the required blue paint = 12.8 litres.

7.   (a)  Number of squares = 2
      Number of triangles = 3 2
     ∴ Ratio =2/3 or 2: 3

     (b) Number of circles = 3
     Number of rectangles = 3
     ∴ Ratio =3/3  or 1: 1


Long Answer:
1. (a) Number of shaded parts = 4
    Number of unshaded parts = 12
    
     
    Required ratio = 1: 3
   
    (b) Number of shaded parts = 2
    Number of unshaded parts = 4
     
     
    Required ratio = 1: 2

2. We have 20, 25, 12, 15
    Product of extremes = 20 × 15 = 300
    Product of middles = 25 × 12 = 300
    Since both the products are same.
    ∴ The four numbers 20, 25, 12, 15 are in proportion.

3.  Let the third term be x.
    ∴ 32, 112, x and 217 are in proportion.
    ∴ 32: 112:: x: 217
 
      
     Thus, the third term = 62.

4.  (a) Since 8, x, x, 50, are in proportion.
    ∴ x × x = 8 × 50
    ⇒ x2 = 400
   ∴ x = 20

    (b) Since 36, 90, 90, x are in proportion.
    ∴ 36 × x = 90 × 90
    ⇒x=(90×90)/36=225
    ∴ x = 225

5.  Number of tables purchased in ₹ 7500 = 10
     Number of tables purchased in ₹ 1 =10/7500
    ∴ Number of tables purchased in ₹ 9000
    =(10×9000)/75000=12

6. Number of pens in 1 packet = 12
    Number of pens in 39 packets = 12 × 39 = 468
    Number of pens in 1 packet = 10
    Number of pens in 52 packets = 10 × 52 = 520
    Now cost of 468 pen = ₹ 374.40
   
   


Assertion and Reason Answers:
(1) (a) A is false but R is true
(2) (b) Both A and R are true and R is the correct explanation of A

 



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