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NCERT 6TH CLASS MATHS KNOWING OUR NUMBERS PART-lll

ANSWER KEY-

Multiple Choice questions:
1.   D. One crore
2.  D. N
3.  D. Smallest 6-digit number
4.  B. 2289
5.  D. 1002
6.  C. MCMLI
7.  D. 2334, 2340
8.  B. DCVIII < MCVIII
9.  B. 7721
10. C. 495
11.  B. 8873
12.  B. 9867
13.  C. MMDCCLXV
14.  C. 1237
15.  A. 12202, 124

Match The Following:



Fill in the blanks:
1.  1 million = ten hundred thousand.
2.  1 crore = tentenlakh.
3.  1 crore = ten million.
4.  1 million = ten lakh.

True /False:
1.  True
2.  False
3.  True
4.  False

Very Short Answer:
1.  1 billion= 100 crore

2.  764298 is the greatest number

3. (a)  73,75,307
    (b)  9,05,00,041
    (c)  7,52,21,302
    (d)  58,423,202

4.  Total number of people visited the zoo = 6000 people
      Total number of children = 2615 children
      Then number of adults = 6000 – 2615 = 3385

5.  Sale of books in the first week = Rs.2,85,891.
      Sale of books in the second week = Rs.4,00,768
∴   Sale for the two weeks together = Rs.2,85,891 + Rs.4,00,768 = Rs.6,86,659.
      The sale was greater in the second week by Rs. 4,00,768 – Rs.2,85,891 i.e., by Rs. 1,14,877.

6.   The greatest number is 42375
       The smallest number is 42329

7.  Expression 13 × (4 + 11) = 13 × 15 = 195
      On reversing the answer = 591
      Adding reversing number to the result i.e., 591 + 195 = 786
      Multiplying it by 13 i.e., 786 × 13 = 10218.

8.  The required number is 101.

9.  The required number is 999.

10.  The number obtained by reversing the digits of 203 = 302.
∴      Difference = 302 – 203 = 99
         Hence, the required number is 99.

11.    438 = 4 × 100 + 3 × 10 + 8.

12.  The greatest five-digit number using the digits 4, 2 and 0 is 44420.

13.  We know that
        1 liter = 1000 mL
∴     300 liters = 300 × 1000 mL = 3,00,000 mL
        Hence, the capacity of water tank = 3 lakh milliliters.

14.  Greatest 6-digit number = 999999
        Successor of it = 999999 + 1 = 1000000
        i. e., smallest 7-digit number.
        Hence, the required successor = 10,00,000.

15.  Let us write 1743 in its expanded form
        1743 = 1000 + 700 + 40 +3
        Place value of 7 = 700
        Hence, the place value of 7 = 700.


Short Answer:

1.  Since 71,25,400 is a seven-digit number and 7,12,540 is a six-digit number.
      So, 71,25,400 is greater than 7,12,540.

         
   
       Hence 71,25,400 is greater than 7,12,540 by 64,12,860.

2.  Given digits are 0, 2, 4, 6, 8
       5 – digit greatest number = 86420;
       5 – digit smallest number = 20468.

3.  The given numbers are 63,854, 63,584, 65,348, 68,543 and 64,835.
      Ascending order is 63,584 ; 63,854 ; 64,835 ; 65,348 ; 68,543
      Even numbers are 63,584, 63,854 and 65,348

4.  Given number Rounded off to tens
(a)  48 → 50
(b)  59 → 60
(c)  64 → 60
(d)  215 → 220

5. (a)  86 × 316
      ∵  86 → 90 [Rounding off to tens] and 316 → 320 [Rounding off to tens]
      So, the estimated product is 90 × 320 = 28800

6.  We have

        
     
        Hence, quotient = 957 and remainder = 0.

7.   First Method:
      (3759 x 231)-(3759 x 213) = 868329 – 800667 = 67662
      Second Method: 3759 x (231 – 213) = 3759 x 18 = 67662
      Hence, the product difference is 67662.

8.  Estimated values are
      25,148 → 25100
      7394 → 7400
      9343 → 9300
      752 → 800
      So, the estimated sum is 25100 + 7400 + 9300 + 800 = 42600
      Hence, the estimated sum is 42600.

9.  Even numbers between 90 and 100, we have 92, 94, 96, 98.
      ∴ 92 = XCII,
          94 = XCIV,
         96 = XCVI,
         98 = XCVIII       

Long Answer:

1.  
       


2. (a) LXXXVI = 50 + 30 + 6 = 86
     (b) LXXV = 50 + 20 + 5 = 75
     (c) XCIX = (100 – 10) + 9 = 99
     (d) XCI = (100 – 10) + 1 = 91

3. Distance covered when she walks one way = 1 km 480 m = 1480 m
     Therefore, the distance covered when she walk both ways in a day = 1480 × 2 m = 2960 m
     Total distance covered by Reena in 6 days = 2960 × 6 m = 17760 m or 17 km 760 m.

4.  Given:
     36 ÷ [5 + {4 × 5 ÷ 2}]
     Using B, O, D, M, A, S

      

5.
    

      Cloth required to stitch 1 pant = 1 m 15 cm
     = 100 cm + 15 cm [∵ 1 m = 100 cm]
     = 115 cm
     Total cloth = 36 m = 36 × 100 cm = 3600 cm
     Therefore number of pants stitched = 3600/115
     Hence, 31 pants can be stitched and cloth left over is 35 cm.

6.
       

     Amount of commodity delivered by P to A = 60 kg
     Amount of commodity delivered by Q to A = 80 – 60 = 20 kg
    Amount of commodity delivered by P to B = 40 kg
    Amount of commodity delivered by Q to B – 90 – 40 = 50 kg
    Amount of commodity delivered by P to C = 20
    Amount of commodity delivered by Q to C = 100 – 20 = 80 kg.
    Now Amount of money to be paid to P by A, B and C = ₹( 60 × 20 + 40 × 20 + 20 × 20)
    = ₹ (1200 + 800 + 400)
    = ₹ 2400
     and amount of money to be paid to Q by A, B and C
    = ₹ (20 × 20 + 50 × 20 + 80 × 20)
    = ₹ (400 + 1000 + 1600) = ₹ 3000
    Hence, the total amount
    = ₹ 2400 + ₹ 3000 = ₹ 5400.

Assertion Reason Answers:
(1.) (a) Both A and R are true and R is the correct explanation of A
(2.)(a) Both A and R are true and R is the correct explanation of A

 



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